What is the asymptotes of f(x)=(x^2-12x+20)/(2x-4) ?

The asymptotes of f(x)=(x^2-12x+20)/(2x-4) is Slant: y= 1/2 x-5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

asymptotes of f(x)=(x^2-12x+20)/(2x-4)

asymptotes

f (x) = \frac{x ^{2} - 12 x + 20}{2 x - 4}

Slant : y = \frac{1}{2} x - 5

Solution steps

Vertical asymptotes of

\frac{x ^{2} - 12 x + 20}{2 x - 4} :

None

Horizontal Asymptotes of

\frac{x ^{2} - 12 x + 20}{2 x - 4} :

None

Slant Asymptotes of

\frac{x ^{2} - 12 x + 20}{2 x - 4} : y = \frac{1}{2} x - 5

Slant : y = \frac{1}{2} x - 5

\frac{6 x ^{2} - 1}{4 - 2 x}

y = \frac{x}{1 - x}

f (x) = \frac{x}{1 + ∣ x ∣}

f (x) = x^{2} + 10 x + 15 - x

f (x) = \frac{7 x}{x ^{2} - 16}

What is the asymptotes of f(x)=(x^2-12x+20)/(2x-4) ?
The asymptotes of f(x)=(x^2-12x+20)/(2x-4) is Slant: y= 1/2 x-5