What is the asymptotes of f(x)=(3(2x+7)(x+8))/(x+1) ?

The asymptotes of f(x)=(3(2x+7)(x+8))/(x+1) is Vertical: x=-1,Slant: y=6x+63

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asymptotes of f(x)=(3(2x+7)(x+8))/(x+1)

asymptotes

f (x) = \frac{3 ( 2 x + 7 ) ( x + 8 )}{x + 1}

Vertical : x = - 1, Slant : y = 6 x + 63

Solution steps

Vertical asymptotes of

\frac{3 ( 2 x + 7 ) ( x + 8 )}{x + 1} : x = - 1

Horizontal Asymptotes of

\frac{3 ( 2 x + 7 ) ( x + 8 )}{x + 1} :

None

Slant Asymptotes of

\frac{3 ( 2 x + 7 ) ( x + 8 )}{x + 1} : y = 6 x + 63

Vertical : x = - 1, Slant : y = 6 x + 63

\frac{- 2 x - 5}{3 x - 5}

f (x) = \frac{4 x - 6}{x + 7}

\frac{1}{3 x ^{2} + 3 x - 18}

f (x) = \frac{x ^{2} + 2 x - 4}{x ^{3} + 1}

f (x) = \frac{2 x ^{3}}{x ^{2} - x + 1}

What is the asymptotes of f(x)=(3(2x+7)(x+8))/(x+1) ?
The asymptotes of f(x)=(3(2x+7)(x+8))/(x+1) is Vertical: x=-1,Slant: y=6x+63