What is the asymptotes of f(x)= 1/(x^2+x-6) ?

The asymptotes of f(x)= 1/(x^2+x-6) is Vertical: x=-3,x=2,Horizontal: y=0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

asymptotes of f(x)= 1/(x^2+x-6)

asymptotes

f (x) = \frac{1}{x ^{2} + x - 6}

Vertical : x = - 3, x = 2, Horizontal : y = 0

Solution steps

Vertical asymptotes of

\frac{1}{x ^{2} + x - 6} : x = - 3, x = 2

Horizontal Asymptotes of

\frac{1}{x ^{2} + x - 6} : y = 0

Slant Asymptotes of

\frac{1}{x ^{2} + x - 6} :

None

Vertical : x = - 3, x = 2, Horizontal : y = 0

f (x) = - \frac{5}{x - 3}

f (x) = 5 x sin (\frac{1}{x})

f (x) = \frac{x ^{2} + 2 x + 1}{7 x ^{2} - x - 8}

f (x) = \frac{6 x + 1}{6 + 3 x}

f (x) = tan (x + \frac{π}{3})

What is the asymptotes of f(x)= 1/(x^2+x-6) ?
The asymptotes of f(x)= 1/(x^2+x-6) is Vertical: x=-3,x=2,Horizontal: y=0