对称性 y=2(-x-3)^2-5

解答

对称性

y = 2 (- x - 3)^{2} - 5

y = - 3

求解步骤

y = 2 (- x - 3)^{2} - 5

改写为标准形式:

y = 2 x^{2} + 12 x + 13

y = 2 x^{2} + 12 x + 13

y = a x^{2} + b x + c

的对称轴是

x = \frac{- b}{2 a}

a = 2, b = 12

y = \frac{- 12}{2 \cdot 2}

整理后得

y = - 3

(- 18, 8), (11, - 15)

x + y = 6

f (x) = \frac{2 x + 1}{3 x ^{2} - x}

y + 1 = \frac{1}{3} x, (2, - 3)

f (x) = \frac{1}{ln ( x - 1 )}