What is the asymptotes of f(x)=(sqrt(4x^2-9))/(x+5) ?

The asymptotes of f(x)=(sqrt(4x^2-9))/(x+5) is Vertical: x=-5,Horizontal: y=2,y=-2

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asymptotes of f(x)=(sqrt(4x^2-9))/(x+5)

asymptotes

f (x) = \frac{4 x ^{2} - 9}{x + 5}

Vertical : x = - 5, Horizontal : y = 2, y = - 2

Solution steps

Vertical asymptotes of

\frac{4 x ^{2} - 9}{x + 5} : x = - 5

Horizontal Asymptotes of

\frac{4 x ^{2} - 9}{x + 5} : y = 2, y = - 2

Slant Asymptotes of

\frac{4 x ^{2} - 9}{x + 5} :

None

Vertical : x = - 5, Horizontal : y = 2, y = - 2

\frac{2 x ^{2} + 6 x}{- 4 x ^{2} + 8 x}

f (x) = \frac{x - 5}{x ^{2} - 7 x + 10}

f (x) = \frac{x ^{2} + 2 x + 1}{x ^{2} + 3 x - 4}

f (x) = \frac{x ^{2} + 9}{x}

f (x) = \frac{2 x + 6}{x ^{2} - 9}

What is the asymptotes of f(x)=(sqrt(4x^2-9))/(x+5) ?
The asymptotes of f(x)=(sqrt(4x^2-9))/(x+5) is Vertical: x=-5,Horizontal: y=2,y=-2