What is the asymptotes of f(x)=(-2x^2-2x)/(x^2-3x-4) ?

The asymptotes of f(x)=(-2x^2-2x)/(x^2-3x-4) is Vertical: x=4,Horizontal: y=-2

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asymptotes of f(x)=(-2x^2-2x)/(x^2-3x-4)

asymptotes

f (x) = \frac{- 2 x ^{2} - 2 x}{x ^{2} - 3 x - 4}

Vertical : x = 4, Horizontal : y = - 2

Solution steps

Vertical asymptotes of

\frac{- 2 x ^{2} - 2 x}{x ^{2} - 3 x - 4} : x = 4

Horizontal Asymptotes of

\frac{- 2 x ^{2} - 2 x}{x ^{2} - 3 x - 4} : y = - 2

Slant Asymptotes of

\frac{- 2 x ^{2} - 2 x}{x ^{2} - 3 x - 4} :

None

Vertical : x = 4, Horizontal : y = - 2

f (x) = \frac{x ^{2} - x - 12}{x + 3}

\frac{1 - 3 x}{1 - x}

f (x) = x^{4} + 2 x^{3} - 2 x^{2} + 2

f (x) = \frac{x ^{2} - 3 x - 4}{2 x ^{2} + x - 1}

x + \frac{9}{x}

What is the asymptotes of f(x)=(-2x^2-2x)/(x^2-3x-4) ?
The asymptotes of f(x)=(-2x^2-2x)/(x^2-3x-4) is Vertical: x=4,Horizontal: y=-2