What is the asymptotes of f(x)=(x^2-3x-4)/(2x^2+x-1) ?

The asymptotes of f(x)=(x^2-3x-4)/(2x^2+x-1) is Vertical: x= 1/2 ,Horizontal: y= 1/2

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asymptotes of f(x)=(x^2-3x-4)/(2x^2+x-1)

asymptotes

f (x) = \frac{x ^{2} - 3 x - 4}{2 x ^{2} + x - 1}

Vertical : x = \frac{1}{2}, Horizontal : y = \frac{1}{2}

Solution steps

Vertical asymptotes of

\frac{x ^{2} - 3 x - 4}{2 x ^{2} + x - 1} : x = \frac{1}{2}

Horizontal Asymptotes of

\frac{x ^{2} - 3 x - 4}{2 x ^{2} + x - 1} : y = \frac{1}{2}

Slant Asymptotes of

\frac{x ^{2} - 3 x - 4}{2 x ^{2} + x - 1} :

None

Vertical : x = \frac{1}{2}, Horizontal : y = \frac{1}{2}

x + \frac{9}{x}

1 + \frac{1}{x} - \frac{1}{x ^{2}}

\frac{x ^{3} - 2 x ^{2} - 3 x}{x ^{2} - 4}

f (x) = 3 (5^{x}) + 2

f (x) = \frac{x ^{2} - 12}{2 x}

What is the asymptotes of f(x)=(x^2-3x-4)/(2x^2+x-1) ?
The asymptotes of f(x)=(x^2-3x-4)/(2x^2+x-1) is Vertical: x= 1/2 ,Horizontal: y= 1/2