What is the domain of f(x)=9sqrt(x)+8 ?

The domain of f(x)=9sqrt(x)+8 is x>= 0

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domain of f(x)=9sqrt(x)+8

domain

f (x) = 9 x + 8

x \geq 0

Interval Notation

[0, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 0

The function domain

x \geq 0

f (x) = - x^{2} + 2 x + 4

\frac{2 x ^{2} - 2 x - 24}{x ^{2} - 4 x + 3}

5 x - y = 1

(0) (20.2)

f (x) = \frac{x - 4}{3 x - x ^{2}}