What is the asymptotes of y=(2x^2)/(1-x^2) ?

The asymptotes of y=(2x^2)/(1-x^2) is Vertical: x=-1,x=1,Horizontal: y=-2

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asymptotes of y=(2x^2)/(1-x^2)

asymptotes

y = \frac{2 x ^{2}}{1 - x ^{2}}

Vertical : x = - 1, x = 1, Horizontal : y = - 2

Solution steps

Vertical asymptotes of

\frac{2 x ^{2}}{1 - x ^{2}} : x = - 1, x = 1

Horizontal Asymptotes of

\frac{2 x ^{2}}{1 - x ^{2}} : y = - 2

Slant Asymptotes of

\frac{2 x ^{2}}{1 - x ^{2}} :

None

Vertical : x = - 1, x = 1, Horizontal : y = - 2

\frac{x ^{2} + x - 6}{x + 2}

f (x) = \frac{5 x - 15}{x ^{2} - 8 x + 15}

h (x) = \frac{x + 1}{x ^{2} - 16}

f (x) = \frac{x ^{2} + 16}{x ^{2} - 16}

f (x) = \frac{x}{- 3 x + 3}

What is the asymptotes of y=(2x^2)/(1-x^2) ?
The asymptotes of y=(2x^2)/(1-x^2) is Vertical: x=-1,x=1,Horizontal: y=-2