What is the asymptotes of f(x)=((x+2))/((x^2-9)) ?

The asymptotes of f(x)=((x+2))/((x^2-9)) is Vertical: x=-3,x=3,Horizontal: y=0

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asymptotes of f(x)=((x+2))/((x^2-9))

asymptotes

f (x) = \frac{( x + 2 )}{( x ^{2} - 9 )}

Vertical : x = - 3, x = 3, Horizontal : y = 0

Solution steps

Vertical asymptotes of

\frac{x + 2}{x ^{2} - 9} : x = - 3, x = 3

Horizontal Asymptotes of

\frac{x + 2}{x ^{2} - 9} : y = 0

Slant Asymptotes of

\frac{x + 2}{x ^{2} - 9} :

None

Vertical : x = - 3, x = 3, Horizontal : y = 0

f (x) = \frac{6 x ^{2} + x - 35}{2 x + 5}

f (x) = (x^{2} + 12) (9 - x^{2})

f (x) = \frac{- 2 x - 6}{x ^{2} + 3 x}

\frac{- x ^{3} - x + 5}{2 x ^{3} + 3 x ^{2} - 7}

f (x) = arctan (e^{4 x} + 1)

What is the asymptotes of f(x)=((x+2))/((x^2-9)) ?
The asymptotes of f(x)=((x+2))/((x^2-9)) is Vertical: x=-3,x=3,Horizontal: y=0