What is the asymptotes of f(x)=(2x^2+x+1)/(4x^2+16) ?

The asymptotes of f(x)=(2x^2+x+1)/(4x^2+16) is Horizontal: y= 1/2

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asymptotes of f(x)=(2x^2+x+1)/(4x^2+16)

asymptotes

f (x) = \frac{2 x ^{2} + x + 1}{4 x ^{2} + 16}

Horizontal : y = \frac{1}{2}

Solution steps

Vertical asymptotes of

\frac{2 x ^{2} + x + 1}{4 x ^{2} + 16} :

None

Horizontal Asymptotes of

\frac{2 x ^{2} + x + 1}{4 x ^{2} + 16} : y = \frac{1}{2}

Slant Asymptotes of

\frac{2 x ^{2} + x + 1}{4 x ^{2} + 16} :

None

Horizontal : y = \frac{1}{2}

f (x) = \frac{x - 1}{( x + 1 ) ^{2}}

f (x) = \frac{( x + 2 )}{( x ^{2} - 16 )}

\frac{- 3 x ^{2} + 3 x}{x + 1}

\frac{x ^{2} + 2 x - 3}{( x - 1 ) ( x ^{2} - 4 )}

f (x) = \frac{( sin ( x ) )}{x}

What is the asymptotes of f(x)=(2x^2+x+1)/(4x^2+16) ?
The asymptotes of f(x)=(2x^2+x+1)/(4x^2+16) is Horizontal: y= 1/2