What is the asymptotes of f(x)=(2x^2)/(x^2-16) ?

The asymptotes of f(x)=(2x^2)/(x^2-16) is Vertical: x=-4,x=4,Horizontal: y=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

asymptotes of f(x)=(2x^2)/(x^2-16)

asymptotes

f (x) = \frac{2 x ^{2}}{x ^{2} - 16}

Vertical : x = - 4, x = 4, Horizontal : y = 2

Solution steps

Vertical asymptotes of

\frac{2 x ^{2}}{x ^{2} - 16} : x = - 4, x = 4

Horizontal Asymptotes of

\frac{2 x ^{2}}{x ^{2} - 16} : y = 2

Slant Asymptotes of

\frac{2 x ^{2}}{x ^{2} - 16} :

None

Vertical : x = - 4, x = 4, Horizontal : y = 2

f (x) = - lo g_{10} (x)

f (x) = \frac{x ^{2} + 9 x + 8}{x ^{3} - 4 x}

\frac{5 x ^{2}}{3 x ^{2} + 7 x}

x^{2} + 1 - x

\frac{3 x + 11}{4 x - 15}

What is the asymptotes of f(x)=(2x^2)/(x^2-16) ?
The asymptotes of f(x)=(2x^2)/(x^2-16) is Vertical: x=-4,x=4,Horizontal: y=2