What is the asymptotes of f(x)=arctan(-e^{4x}) ?

The asymptotes of f(x)=arctan(-e^{4x}) is Horizontal: y=-pi/2 ,y=0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

asymptotes of f(x)=arctan(-e^{4x})

asymptotes

f (x) = arctan (- e^{4 x})

Horizontal : y = - \frac{π}{2}, y = 0

Solution steps

Vertical asymptotes of

arctan (- e^{4 x}) :

None

Horizontal Asymptotes of

arctan (- e^{4 x}) : y = - \frac{π}{2}, y = 0

Slant Asymptotes of

arctan (- e^{4 x}) :

None

Horizontal : y = - \frac{π}{2}, y = 0

\frac{( x + 4 )}{x ^{2} + x - 12}

f (x) = \frac{2 x ^{2} + 5 x - 7}{x - 3}

f (x) = \frac{( 4 x + 1 )}{x + 2}

\frac{2 x + 1}{x ^{2}}

f (x) = sec (2 x)

What is the asymptotes of f(x)=arctan(-e^{4x}) ?
The asymptotes of f(x)=arctan(-e^{4x}) is Horizontal: y=-pi/2 ,y=0