What is the asymptotes of y=(x^2-6x+12)/(x-4) ?

The asymptotes of y=(x^2-6x+12)/(x-4) is Vertical: x=4,Slant: y=x-2

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asymptotes of y=(x^2-6x+12)/(x-4)

asymptotes

y = \frac{x ^{2} - 6 x + 12}{x - 4}

Vertical : x = 4, Slant : y = x - 2

Solution steps

Vertical asymptotes of

\frac{x ^{2} - 6 x + 12}{x - 4} : x = 4

Horizontal Asymptotes of

\frac{x ^{2} - 6 x + 12}{x - 4} :

None

Slant Asymptotes of

\frac{x ^{2} - 6 x + 12}{x - 4} : y = x - 2

Vertical : x = 4, Slant : y = x - 2

f (x) = (x + 2) (x + 1) e^{- x}

x^{3} - 6 x^{2} + 9 x + 1

f (x) = \frac{x ^{2} - 7 x + 12}{- 5 x + 15}

f (x) = \frac{11}{1 + 2 ^{x}}

f (x) = \frac{3 x ^{3} + 2 x ^{2} - 5}{x ^{2} - 1}

What is the asymptotes of y=(x^2-6x+12)/(x-4) ?
The asymptotes of y=(x^2-6x+12)/(x-4) is Vertical: x=4,Slant: y=x-2