What is the asymptotes of f(x)=(x^2-16)/(2x^2+8x) ?

The asymptotes of f(x)=(x^2-16)/(2x^2+8x) is Vertical: x=0,Horizontal: y= 1/2

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asymptotes of f(x)=(x^2-16)/(2x^2+8x)

asymptotes

f (x) = \frac{x ^{2} - 16}{2 x ^{2} + 8 x}

Vertical : x = 0, Horizontal : y = \frac{1}{2}

Solution steps

Vertical asymptotes of

\frac{x ^{2} - 16}{2 x ^{2} + 8 x} : x = 0

Horizontal Asymptotes of

\frac{x ^{2} - 16}{2 x ^{2} + 8 x} : y = \frac{1}{2}

Slant Asymptotes of

\frac{x ^{2} - 16}{2 x ^{2} + 8 x} :

None

Vertical : x = 0, Horizontal : y = \frac{1}{2}

f (x) = arctan (e^{- 3 x} - 1)

f (x) = \frac{x ^{3}}{x ^{2} - x - 2}

y = 2 tan (2 x)

f (x) = 2 tan (x)

f (x) = \frac{x ^{2} - 9}{3 x + 1}

What is the asymptotes of f(x)=(x^2-16)/(2x^2+8x) ?
The asymptotes of f(x)=(x^2-16)/(2x^2+8x) is Vertical: x=0,Horizontal: y= 1/2