What is the domain of f(x)=sqrt(ln(x^2-6x+9)) ?

The domain of f(x)=sqrt(ln(x^2-6x+9)) is x = 4

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domain of f(x)=sqrt(ln(x^2-6x+9))

domain

f (x) = ln (x^{2} - 6 x + 9)

x \leq 2 or x \geq 4

Interval Notation

(- \infty, 2] \cup [4, \infty)

Solution steps

Find non-negative values for radicals:

x \leq 2 or x \geq 4

The function domain

x \leq 2 or x \geq 4

f (x) = - x + 8

x^{2} + 5 x

x 9 - x^{2}

f (x) = 3 x - 18

2 x - 8

What is the domain of f(x)=sqrt(ln(x^2-6x+9)) ?
The domain of f(x)=sqrt(ln(x^2-6x+9)) is x<= 2\lor x>= 4