What is the asymptotes of f(x)=(4x^2-1)/(2x+1) ?

The asymptotes of f(x)=(4x^2-1)/(2x+1) is Slant: y=2x-1

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asymptotes of f(x)=(4x^2-1)/(2x+1)

asymptotes

f (x) = \frac{4 x ^{2} - 1}{2 x + 1}

Slant : y = 2 x - 1

Solution steps

Vertical asymptotes of

\frac{4 x ^{2} - 1}{2 x + 1} :

None

Horizontal Asymptotes of

\frac{4 x ^{2} - 1}{2 x + 1} :

None

Slant Asymptotes of

\frac{4 x ^{2} - 1}{2 x + 1} : y = 2 x - 1

Slant : y = 2 x - 1

f (x) = \frac{x - 4}{x ^{2} - x - 6}

f (x) = \frac{3 x - 21}{x ^{2} - 8 x + 7}

f (x) = \frac{x ( 1 + 3 x )}{x ^{2} + x - 2}

f (x) = \frac{1}{x ^{2} - 9 x + 20}

16 y = 2 x^{2} + y x^{2}

What is the asymptotes of f(x)=(4x^2-1)/(2x+1) ?
The asymptotes of f(x)=(4x^2-1)/(2x+1) is Slant: y=2x-1