What is the asymptotes of y= x/(1+3x) ?

The asymptotes of y= x/(1+3x) is Vertical: x=-1/3 ,Horizontal: y= 1/3

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asymptotes of y= x/(1+3x)

asymptotes

y = \frac{x}{1 + 3 x}

Vertical : x = - \frac{1}{3}, Horizontal : y = \frac{1}{3}

Solution steps

Vertical asymptotes of

\frac{x}{1 + 3 x} : x = - \frac{1}{3}

Horizontal Asymptotes of

\frac{x}{1 + 3 x} : y = \frac{1}{3}

Slant Asymptotes of

\frac{x}{1 + 3 x} :

None

Vertical : x = - \frac{1}{3}, Horizontal : y = \frac{1}{3}

(x^{2} + 12) (4 - x^{2})

\frac{x + 3}{x - 4}

f (x) = \frac{2 x - 1}{2 ( x - 1 ) ^{2}}

f (x) = x + \frac{4}{x ^{2} + 1}

f (x) = \frac{x - 1}{x ^{2} - 4 x - 5}

What is the asymptotes of y= x/(1+3x) ?
The asymptotes of y= x/(1+3x) is Vertical: x=-1/3 ,Horizontal: y= 1/3