What is the asymptotes of f(x)= 1/((x^2-4)) ?

The asymptotes of f(x)= 1/((x^2-4)) is Vertical: x=-2,x=2,Horizontal: y=0

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asymptotes of f(x)= 1/((x^2-4))

asymptotes

f (x) = \frac{1}{( x ^{2} - 4 )}

Vertical : x = - 2, x = 2, Horizontal : y = 0

Solution steps

Vertical asymptotes of

\frac{1}{x ^{2} - 4} : x = - 2, x = 2

Horizontal Asymptotes of

\frac{1}{x ^{2} - 4} : y = 0

Slant Asymptotes of

\frac{1}{x ^{2} - 4} :

None

Vertical : x = - 2, x = 2, Horizontal : y = 0

f (x) = lo g_{2} (x + 8)

\frac{1}{( x + 2 ) ^{2}}

f (x) = \frac{2 x}{x ^{2} - 9}

f (x) = \frac{( ( x + 1 ) ^{3} )}{( x - 1 ) ^{2}}

f (x) = lo g_{2} (x - 8)

What is the asymptotes of f(x)= 1/((x^2-4)) ?
The asymptotes of f(x)= 1/((x^2-4)) is Vertical: x=-2,x=2,Horizontal: y=0