What is the asymptotes of y= 1/(x+1) ?

The asymptotes of y= 1/(x+1) is Vertical: x=-1,Horizontal: y=0

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asymptotes of y= 1/(x+1)

asymptotes

y = \frac{1}{x + 1}

Vertical : x = - 1, Horizontal : y = 0

Solution steps

Vertical asymptotes of

\frac{1}{x + 1} : x = - 1

Horizontal Asymptotes of

\frac{1}{x + 1} : y = 0

Slant Asymptotes of

\frac{1}{x + 1} :

None

Vertical : x = - 1, Horizontal : y = 0

f (x) = \frac{( x ^{2} - 1 )}{- x ^{3} - x ^{2}}

f (x) = \frac{- 2 x + 6}{x ^{2} - 4 x + 3}

f (x) = \frac{x ^{2} - 6 x + 8}{2 x - 4}

f (x) = \frac{( x ^{2} + x - 6 )}{( x - 3 )}

f (x) = \frac{- 3 x + 12}{x ^{2} - 4 x}

What is the asymptotes of y= 1/(x+1) ?
The asymptotes of y= 1/(x+1) is Vertical: x=-1,Horizontal: y=0