What is the asymptotes of f(x)=(2x^3-x^2-3x)/(x^2-1) ?

The asymptotes of f(x)=(2x^3-x^2-3x)/(x^2-1) is Vertical: x=1,Slant: y=2x-1

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asymptotes of f(x)=(2x^3-x^2-3x)/(x^2-1)

asymptotes

f (x) = \frac{2 x ^{3} - x ^{2} - 3 x}{x ^{2} - 1}

Vertical : x = 1, Slant : y = 2 x - 1

Solution steps

Vertical asymptotes of

\frac{2 x ^{3} - x ^{2} - 3 x}{x ^{2} - 1} : x = 1

Horizontal Asymptotes of

\frac{2 x ^{3} - x ^{2} - 3 x}{x ^{2} - 1} :

None

Slant Asymptotes of

\frac{2 x ^{3} - x ^{2} - 3 x}{x ^{2} - 1} : y = 2 x - 1

Vertical : x = 1, Slant : y = 2 x - 1

f (x) = \frac{2 x ^{2} + 1}{4 x - x ^{2}}

f (x) = \frac{2}{4 x ^{2} + 10 x - 6}

f (x) = \frac{1}{x + 17}

f (x) = \frac{2}{x} + \frac{x}{2}

f (x) = 2^{x - 4}

What is the asymptotes of f(x)=(2x^3-x^2-3x)/(x^2-1) ?
The asymptotes of f(x)=(2x^3-x^2-3x)/(x^2-1) is Vertical: x=1,Slant: y=2x-1