What is the asymptotes of f(x)=(x^2-9)/(x^2-x-6) ?

The asymptotes of f(x)=(x^2-9)/(x^2-x-6) is Vertical: x=-2,Horizontal: y=1

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asymptotes of f(x)=(x^2-9)/(x^2-x-6)

asymptotes

f (x) = \frac{x ^{2} - 9}{x ^{2} - x - 6}

Vertical : x = - 2, Horizontal : y = 1

Solution steps

Vertical asymptotes of

\frac{x ^{2} - 9}{x ^{2} - x - 6} : x = - 2

Horizontal Asymptotes of

\frac{x ^{2} - 9}{x ^{2} - x - 6} : y = 1

Slant Asymptotes of

\frac{x ^{2} - 9}{x ^{2} - x - 6} :

None

Vertical : x = - 2, Horizontal : y = 1

f (x) = \frac{( 5 + 2 ^{x} )}{( 1 - 2 ^{x} )}

\frac{x ^{2}}{x - 4}

(\frac{1}{3})^{x} + 1

f (x) = \frac{2 x + 1}{x ^{2} ( x + 1 ) ^{2}}

f (x) = - 7, x = - 2

What is the asymptotes of f(x)=(x^2-9)/(x^2-x-6) ?
The asymptotes of f(x)=(x^2-9)/(x^2-x-6) is Vertical: x=-2,Horizontal: y=1