What is the asymptotes of f(x)=(6x^2+7x-9)/(2x+1) ?

The asymptotes of f(x)=(6x^2+7x-9)/(2x+1) is Vertical: x=-1/2 ,Slant: y=3x+2

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asymptotes of f(x)=(6x^2+7x-9)/(2x+1)

asymptotes

f (x) = \frac{6 x ^{2} + 7 x - 9}{2 x + 1}

Vertical : x = - \frac{1}{2}, Slant : y = 3 x + 2

Solution steps

Vertical asymptotes of

\frac{6 x ^{2} + 7 x - 9}{2 x + 1} : x = - \frac{1}{2}

Horizontal Asymptotes of

\frac{6 x ^{2} + 7 x - 9}{2 x + 1} :

None

Slant Asymptotes of

\frac{6 x ^{2} + 7 x - 9}{2 x + 1} : y = 3 x + 2

Vertical : x = - \frac{1}{2}, Slant : y = 3 x + 2

f (x) = \frac{2 x + 1}{x ^{2} - 9}

f (x) = 0. 8^{x}

\frac{x + 7}{7 x + 49}

10 - 6 ln (x)

f (x) = - 3^{x - 1} - 3

What is the asymptotes of f(x)=(6x^2+7x-9)/(2x+1) ?
The asymptotes of f(x)=(6x^2+7x-9)/(2x+1) is Vertical: x=-1/2 ,Slant: y=3x+2