What is the asymptotes of f(x)=((x^2-6x-1))/(x+3) ?

The asymptotes of f(x)=((x^2-6x-1))/(x+3) is Vertical: x=-3,Slant: y=x-9

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asymptotes of f(x)=((x^2-6x-1))/(x+3)

asymptotes

f (x) = \frac{( x ^{2} - 6 x - 1 )}{x + 3}

Vertical : x = - 3, Slant : y = x - 9

Solution steps

Vertical asymptotes of

\frac{x ^{2} - 6 x - 1}{x + 3} : x = - 3

Horizontal Asymptotes of

\frac{x ^{2} - 6 x - 1}{x + 3} :

None

Slant Asymptotes of

\frac{x ^{2} - 6 x - 1}{x + 3} : y = x - 9

Vertical : x = - 3, Slant : y = x - 9

f (x) = \frac{4}{10 x ^{2} - 411}

f (x) = \frac{4}{x} + 1

f (x) = \frac{x ^{3} + x ^{2} + 3}{x ^{2} - 9}

f (x) = \frac{( x + 7 )}{( x + 3 ) ( x - 5 )}

f (x) = - 2^{(- 2 + 3 x)} - 4

What is the asymptotes of f(x)=((x^2-6x-1))/(x+3) ?
The asymptotes of f(x)=((x^2-6x-1))/(x+3) is Vertical: x=-3,Slant: y=x-9