What is the asymptotes of f(x)=(x^2+x-6)/(x^2-9) ?

The asymptotes of f(x)=(x^2+x-6)/(x^2-9) is Vertical: x=3,Horizontal: y=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

asymptotes of f(x)=(x^2+x-6)/(x^2-9)

asymptotes

f (x) = \frac{x ^{2} + x - 6}{x ^{2} - 9}

Vertical : x = 3, Horizontal : y = 1

Solution steps

Vertical asymptotes of

\frac{x ^{2} + x - 6}{x ^{2} - 9} : x = 3

Horizontal Asymptotes of

\frac{x ^{2} + x - 6}{x ^{2} - 9} : y = 1

Slant Asymptotes of

\frac{x ^{2} + x - 6}{x ^{2} - 9} :

None

Vertical : x = 3, Horizontal : y = 1

f (x) = \frac{2 - 3 x}{x ^{2} - 2 x - 15}

f (x) = \frac{- 6 x ^{2} - 5 x + 1}{2 x + 1}

f (x) = 3 + \frac{( 3 x + 2 )}{x}

f (x) = \frac{( 3 x - 2 )}{( x + 1 )}

f (x) = 3^{x - 1} + 2

What is the asymptotes of f(x)=(x^2+x-6)/(x^2-9) ?
The asymptotes of f(x)=(x^2+x-6)/(x^2-9) is Vertical: x=3,Horizontal: y=1