What is the asymptotes of f(x)=(x+1)/(x^2+4x) ?

The asymptotes of f(x)=(x+1)/(x^2+4x) is Vertical: x=-4,x=0,Horizontal: y=0

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asymptotes of f(x)=(x+1)/(x^2+4x)

asymptotes

f (x) = \frac{x + 1}{x ^{2} + 4 x}

Vertical : x = - 4, x = 0, Horizontal : y = 0

Solution steps

Vertical asymptotes of

\frac{x + 1}{x ^{2} + 4 x} : x = - 4, x = 0

Horizontal Asymptotes of

\frac{x + 1}{x ^{2} + 4 x} : y = 0

Slant Asymptotes of

\frac{x + 1}{x ^{2} + 4 x} :

None

Vertical : x = - 4, x = 0, Horizontal : y = 0

\frac{x ( x - 5 ) ^{2}}{( x + 7 ) ^{3}}

f (x) = 4^{x - 1}

f (x) = \frac{6 x ^{2} + 1}{2 x ^{2} + 7 x - 4}

\frac{( x + 4 ) ( x + 4 )}{( x + 1 ) ( x - 4 )}

f (x) = \frac{4}{( x + 2 ) ^{2}}

What is the asymptotes of f(x)=(x+1)/(x^2+4x) ?
The asymptotes of f(x)=(x+1)/(x^2+4x) is Vertical: x=-4,x=0,Horizontal: y=0