What is the asymptotes of f(x)=-(16)/(x^2-2x-8) ?

The asymptotes of f(x)=-(16)/(x^2-2x-8) is Vertical: x=-2,x=4,Horizontal: y=0

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asymptotes of f(x)=-(16)/(x^2-2x-8)

asymptotes

f (x) = - \frac{16}{x ^{2} - 2 x - 8}

Vertical : x = - 2, x = 4, Horizontal : y = 0

Solution steps

Vertical asymptotes of

- \frac{16}{x ^{2} - 2 x - 8} : x = - 2, x = 4

Horizontal Asymptotes of

- \frac{16}{x ^{2} - 2 x - 8} : y = 0

Slant Asymptotes of

- \frac{16}{x ^{2} - 2 x - 8} :

None

Vertical : x = - 2, x = 4, Horizontal : y = 0

f (x) = \frac{( 3 x + 1 )}{x + 1}

\frac{x ^{3} + 2 x + 4}{2 x ^{2} + 2}

\frac{8 x ^{2} + 1}{x ^{2} + 4 x + 3}

f (x) = \frac{x ^{2} + 5 x - 5}{x + 1}

y = \frac{x ^{2} - 2 x + 2}{x - 1}

What is the asymptotes of f(x)=-(16)/(x^2-2x-8) ?
The asymptotes of f(x)=-(16)/(x^2-2x-8) is Vertical: x=-2,x=4,Horizontal: y=0