What is the asymptotes of f(x)=(x^2+5x-5)/(x+1) ?

The asymptotes of f(x)=(x^2+5x-5)/(x+1) is Vertical: x=-1,Slant: y=x+4

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asymptotes of f(x)=(x^2+5x-5)/(x+1)

asymptotes

f (x) = \frac{x ^{2} + 5 x - 5}{x + 1}

Vertical : x = - 1, Slant : y = x + 4

Solution steps

Vertical asymptotes of

\frac{x ^{2} + 5 x - 5}{x + 1} : x = - 1

Horizontal Asymptotes of

\frac{x ^{2} + 5 x - 5}{x + 1} :

None

Slant Asymptotes of

\frac{x ^{2} + 5 x - 5}{x + 1} : y = x + 4

Vertical : x = - 1, Slant : y = x + 4

y = \frac{x ^{2} - 2 x + 2}{x - 1}

f (x) = \frac{1}{x ^{2} - 2 x + 1}

f (x) = \frac{x}{2 x ^{2} - 32}

f (x) = \frac{( x ^{2} + x - 6 )}{2 x ^{2} - 18}

f (x) = y (x - 3)^{2} = x^{2} + 9

What is the asymptotes of f(x)=(x^2+5x-5)/(x+1) ?
The asymptotes of f(x)=(x^2+5x-5)/(x+1) is Vertical: x=-1,Slant: y=x+4