What is the asymptotes of f(x)=((4x^2+1))/(x^2-1) ?

The asymptotes of f(x)=((4x^2+1))/(x^2-1) is Vertical: x=-1,x=1,Horizontal: y=4

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asymptotes of f(x)=((4x^2+1))/(x^2-1)

asymptotes

f (x) = \frac{( 4 x ^{2} + 1 )}{x ^{2} - 1}

Vertical : x = - 1, x = 1, Horizontal : y = 4

Solution steps

Vertical asymptotes of

\frac{4 x ^{2} + 1}{x ^{2} - 1} : x = - 1, x = 1

Horizontal Asymptotes of

\frac{4 x ^{2} + 1}{x ^{2} - 1} : y = 4

Slant Asymptotes of

\frac{4 x ^{2} + 1}{x ^{2} - 1} :

None

Vertical : x = - 1, x = 1, Horizontal : y = 4

p (x) = tan (x - \frac{π}{6})

f (x) = arctan (e^{- 5 x})

- lo g_{4} (x)

f (x) = (x + 0)^{2} + y^{2} = 1

\frac{t - 1}{t ^{2} + 8 t - 3 t}

What is the asymptotes of f(x)=((4x^2+1))/(x^2-1) ?
The asymptotes of f(x)=((4x^2+1))/(x^2-1) is Vertical: x=-1,x=1,Horizontal: y=4