What is the y=ln(x^2)+sin(x) ?

The y=ln(x^2)+sin(x) is Domain: x 0 Intercepts: None Asymptotes: Vertical x=0

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y=ln(x^2)+sin(x)

y = ln (x^{2}) + sin (x)

Domain : x < 0 or x > 0

Intercepts : None

Asymptotes : Vertical x = 0

Interval Notation

Domain : (- \infty, 0) \cup (0, \infty)

Solution steps

Domain of

ln (x^{2}) + sin (x) : x < 0 or x > 0

Axis interception points of

ln (x^{2}) + sin (x) :

None

Asymptotes of

ln (x^{2}) + sin (x) :

Vertical

: x = 0

y = \frac{2}{( ( 3 x + 1 ) ^{2} )} + \frac{4}{( ( 4 x - 3 ) ^{2} )}

f (t) = \frac{cos ^{3} ( t )}{t}

y = (e^{x} + e^{- x})^{2}

y = 7 x^{2} + 2 x + 3

f (x) = \frac{( x - 7 )}{( x + 12 )}

What is the y=ln(x^2)+sin(x) ?
The y=ln(x^2)+sin(x) is Domain: x<0\lor x>0<br/>Intercepts: None<br/>Asymptotes: Vertical x=0