What is the domain of f(x)= 1/((x+3)^{1/2)} ?

The domain of f(x)= 1/((x+3)^{1/2)} is x>-3

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domain of f(x)= 1/((x+3)^{1/2)}

domain

f (x) = \frac{1}{( x + 3 ) ^{\frac{1}{2}}}

x > - 3

Interval Notation

(- 3, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 3

Find undefined (singularity) points:

x = - 3

Combine real regions and undefined points for final function domain

x > - 3

f (x) = \frac{3}{x - 5}

\frac{2 x + 3}{x - 1}

\frac{5}{6} (x + 1)^{2} (x - 1) (x - 4)

f (x) = 3 x^{2} - x^{10}

\frac{x}{9 x + 64}

What is the domain of f(x)= 1/((x+3)^{1/2)} ?
The domain of f(x)= 1/((x+3)^{1/2)} is x>-3