What is the domain of 5/6 (x+1)^2(x-1)(x-4) ?

The domain of 5/6 (x+1)^2(x-1)(x-4) is -infinity <x<infinity

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domain of 5/6 (x+1)^2(x-1)(x-4)

domain

\frac{5}{6} (x + 1)^{2} (x - 1) (x - 4)

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

f (x) = 3 x^{2} - x^{10}

\frac{x}{9 x + 64}

f (x) = \frac{( x ^{2} - x - 6 )}{x ^{2} - 4}

f (x) = 2 x - 8 x

(5.3) (2)

What is the domain of 5/6 (x+1)^2(x-1)(x-4) ?
The domain of 5/6 (x+1)^2(x-1)(x-4) is -infinity <x<infinity