What is the domain of (cot(4xpi))/(cos(7/8)) ?

The domain of (cot(4xpi))/(cos(7/8)) is 1/4 n<x< 1/4+1/4 n

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domain of (cot(4xpi))/(cos(7/8))

domain

\frac{cot ( 4 x π )}{cos ( \frac{7}{8} )}

\frac{1}{4} n < x < \frac{1}{4} + \frac{1}{4} n

Interval Notation

(\frac{1}{4} n, \frac{1}{4} + \frac{1}{4} n)

Solution steps

Take the denominator(s) of

\frac{cot ( 4 x π )}{cos ( \frac{7}{8} )}

and compare to zero:

x = \frac{1}{4} n

Periodicity of

\frac{cot ( 4 x π )}{cos ( \frac{7}{8} )} : \frac{1}{4}

Combine period:

\frac{1}{4} n \leq x < \frac{1}{4} + \frac{1}{4} n

and undefined points.

The domain is

\frac{1}{4} n < x < \frac{1}{4} + \frac{1}{4} n

x^{3} - 3 x^{2} - x + 4

f (x) = 4 sin (2 x - π)

f (x) = 4 x^{2} - 5

f (x) = - 4^{x + 5}

y = - \frac{3}{4} x - \frac{3}{2}

What is the domain of (cot(4xpi))/(cos(7/8)) ?
The domain of (cot(4xpi))/(cos(7/8)) is 1/4 n<x< 1/4+1/4 n