What is ((1+x^2)}{10}-\frac{(3x))/5 ?

The solution to ((1+x^2)}{10}-\frac{(3x))/5 is (1+x^2-6x)/(10)

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simplify ((1+x^2)}{10}-\frac{(3x))/5

simplify

\frac{( 1 + x ^{2} )}{10} - \frac{( 3 x )}{5}

\frac{1 + x ^{2} - 6 x}{10}

Solution steps

\frac{1 + x ^{2}}{10} - \frac{3 x}{5}

Least Common Multiplier of

10, 5 : 10

Adjust Fractions based on the LCM

= \frac{1 + x ^{2}}{10} - \frac{6 x}{10}

Apply the fraction rule:

\frac{a}{c} - \frac{b}{c} = \frac{a - b}{c}

= \frac{1 + x ^{2} - 6 x}{10}

y = \frac{( 1 + x )}{2}

p (x) = 4^{x} \cdot 1 0^{x + 2} \cdot 8^{- x} \cdot 5^{- (x + 1)}

lo g_{0} (a (a + 3))

x^{5} - 5 x

p (x) = x^{2} - 1, - 1, x = 1

What is ((1+x^2)}{10}-\frac{(3x))/5 ?
The solution to ((1+x^2)}{10}-\frac{(3x))/5 is (1+x^2-6x)/(10)