What is the domain of f(x)=(1/(sqrt(x)))/(x^2-4) ?

The domain of f(x)=(1/(sqrt(x)))/(x^2-4) is 0 2

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domain of f(x)=(1/(sqrt(x)))/(x^2-4)

domain

f (x) = \frac{\frac{1}{x}}{x ^{2} - 4}

0 < x < 2 or x > 2

Interval Notation

(0, 2) \cup (2, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 0

Find undefined (singularity) points:

x = 2, x = - 2, x = 0

Combine real regions and undefined points for final function domain

0 < x < 2 or x > 2

(- 6 5), (- 6 - 5)

f (x) = \frac{7 x + 63}{9 x}

f (x) = 2 x - 1 + 3

3^{2 x - 1}

- 5 sin (29 (x - 3)) - 8

What is the domain of f(x)=(1/(sqrt(x)))/(x^2-4) ?
The domain of f(x)=(1/(sqrt(x)))/(x^2-4) is 0<x<2\lor x>2