What is the axis y=18x^2+14x ?

The axis y=18x^2+14x is x=-7/18

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axis y=18x^2+14x

axis

y = 18 x^{2} + 14 x

x = - \frac{7}{18}

Solution steps

y = 18 x^{2} + 14 x

Rewrite

y = 18 x^{2} + 14 x

in the standard form

4 \cdot \frac{1}{72} (y - (- \frac{49}{18})) = (x - (- \frac{7}{18}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{7}{18}, - \frac{49}{18}), p = \frac{1}{72}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = - \frac{7}{18}

x = (y)^{4} + 6 (y)^{2} - 1

x^{2} - 24 y + 48 = 0

y = 2 x^{2} + 8 x + 4

y = 48 x - 6 x^{2}

y = 3 x^{2} + 6 x - 45