What is the axis y=-x^2-6x-3 ?

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axis y=-x^2-6x-3

axis

y = - x^{2} - 6 x - 3

x = - 3

Solution steps

y = - x^{2} - 6 x - 3

Rewrite

y = - x^{2} - 6 x - 3

in the standard form

4 (- \frac{1}{4}) (y - 6) = (x - (- 3))^{2}

Therefore parabola properties are:

(h, k) = (- 3, 6), p = - \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = - 3

y = x^{2} - 4 x - 32

(x + 2)^{2} = - 8 (y + 3)

y = \frac{1 + x ^{2} - 8 x}{5}

y^{2} + 6 x - 4 y - 11 = 0

(x + 3)^{2} = 2 (y - 4)