What is the axis y=-2x^2-8x-3 ?

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axis y=-2x^2-8x-3

axis

y = - 2 x^{2} - 8 x - 3

x = - 2

Solution steps

y = - 2 x^{2} - 8 x - 3

Rewrite

y = - 2 x^{2} - 8 x - 3

in the standard form

4 (- \frac{1}{8}) (y - 5) = (x - (- 2))^{2}

Therefore parabola properties are:

(h, k) = (- 2, 5), p = - \frac{1}{8}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = - 2

y = - \frac{13}{11} (x + 3)^{2} + 1

y = (x - 3)^{2} - 2

y = \frac{x ^{2}}{6}

y^{2} - 6 y - 8 x + 17 = 0

y = (x + 2) (x - 2)