What is the axis y=(x^2)/6 ?

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axis y=(x^2)/6

axis

y = \frac{x ^{2}}{6}

x = 0

Solution steps

y = \frac{x ^{2}}{6}

Rewrite

y = \frac{x ^{2}}{6}

in the standard form:

4 \cdot \frac{3}{2} (y - 0) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = \frac{3}{2}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 0

y^{2} - 6 y - 8 x + 17 = 0

y = (x + 2) (x - 2)

x - 3 + y^{2} = 2

(x + 5)^{2} = - 20 (y - 2)

y = (x + 1)^{2} + 5