What is the axis y^2=40x ?

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axis y^2=40x

axis

y^{2} = 40 x

y = 0

Solution steps

y^{2} = 40 x

Rewrite

y^{2} = 40 x

in the standard form:

4 \cdot 10 (x - 0) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = 10

Parabola is of the form

4 p (x - h) = (y - k)^{2}

and is symmetric around the

x

-axis

Axis of symmetry is a line parallel to the

x

-axis which intersects the vertex:

y = 0

y = - x^{2} + 64 x - 292

y = - 45 x^{2} - 27 x + 2

y = - \frac{1}{2} (x - 3)^{2} - 8

y = x^{2} + 6 x + 9

y = 2 x^{2} - 5 x - 6