What is the axis y=-2x^2-3 ?

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axis y=-2x^2-3

axis

y = - 2 x^{2} - 3

x = 0

Solution steps

y = - 2 x^{2} - 3

Rewrite

y = - 2 x^{2} - 3

in the standard form:

4 (- \frac{1}{8}) (y - (- 3)) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, - 3), p = - \frac{1}{8}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 0

x = \frac{1}{8} y^{2}

y = x^{2} + 19 x + 60

y = 2 x^{2} + 8 x - 24

- y^{2} + x - 4 = 0

x = - (y - 2)^{2} - 3