What is the axis-y^2+x-4=0 ?

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

axis-y^2+x-4=0

axis

- y^{2} + x - 4 = 0

y = 0

Solution steps

- y^{2} + x - 4 = 0

Rewrite

- y^{2} + x - 4 = 0

in the standard form:

4 \cdot \frac{1}{4} (x - 4) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (4, 0), p = \frac{1}{4}

Parabola is of the form

4 p (x - h) = (y - k)^{2}

and is symmetric around the

x

-axis

Axis of symmetry is a line parallel to the

x

-axis which intersects the vertex:

y = 0

x = - (y - 2)^{2} - 3

y = x^{2} - 2 x

y = (x + 5) (x + 3)

y^{2} = - 24 x

(x + 5)^{2} = - 4 (y - 4)