What is the axis y=x^2-2x ?

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axis y=x^2-2x

axis

y = x^{2} - 2 x

x = 1

Solution steps

y = x^{2} - 2 x

Rewrite

y = x^{2} - 2 x

in the standard form

4 \cdot \frac{1}{4} (y - (- 1)) = (x - 1)^{2}

Therefore parabola properties are:

(h, k) = (1, - 1), p = \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 1

y = (x + 5) (x + 3)

y^{2} = - 24 x

(x + 5)^{2} = - 4 (y - 4)

- 4 y^{2} - 12 y + 1 = 3 x - 5

(y - 2)^{2} = 8 (x - 4)