What is the axis (x+5)^2=-4(y-4) ?

The axis (x+5)^2=-4(y-4) is x=-5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

axis (x+5)^2=-4(y-4)

axis

(x + 5)^{2} = - 4 (y - 4)

x = - 5

Solution steps

(x + 5)^{2} = - 4 (y - 4)

Rewrite

(x + 5)^{2} = - 4 (y - 4)

in the standard form:

4 (- 1) (y - 4) = (x - (- 5))^{2}

Therefore parabola properties are:

(h, k) = (- 5, 4), p = - 1

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = - 5

- 4 y^{2} - 12 y + 1 = 3 x - 5

(y - 2)^{2} = 8 (x - 4)

y = (x + 5) (x + 4)

y = 8 x^{2} + 7 x - 1

y = x^{2} - 64