What is the axis y=x^2-64 ?

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axis y=x^2-64

axis

y = x^{2} - 64

x = 0

Solution steps

y = x^{2} - 64

Rewrite

y = x^{2} - 64

in the standard form:

4 \cdot \frac{1}{4} (y - (- 64)) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, - 64), p = \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 0

x = 3 y^{2}

4 y = - x^{2} - 12 x - 48

y = - 4 (x + 10)^{2} + 6

(x + 1)^{2} = - 3 (y - 6)

y = 10 x^{2} + 1 - 6 x