What is the axis-3y=x^2-8x+37 ?

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axis-3y=x^2-8x+37

axis

- 3 y = x^{2} - 8 x + 37

x = 4

Solution steps

- 3 y = x^{2} - 8 x + 37

Rewrite

- 3 y = x^{2} - 8 x + 37

in the standard form

4 (- \frac{3}{4}) (y - (- 7)) = (x - 4)^{2}

Therefore parabola properties are:

(h, k) = (4, - 7), p = - \frac{3}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 4

y = - 2 x^{2} + 12 x - 10

y = 2 x^{2} - 12 x + 18

x^{2} - 8 y = 0

y = - 9 x^{2} + 700 x - 6005

(y - 2)^{2} = 40 (x - 2)