What is the axis (y-2)^2=40(x-2) ?

The axis (y-2)^2=40(x-2) is y=2

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axis (y-2)^2=40(x-2)

axis

(y - 2)^{2} = 40 (x - 2)

y = 2

Solution steps

(y - 2)^{2} = 40 (x - 2)

Rewrite

(y - 2)^{2} = 40 (x - 2)

in the standard form:

4 \cdot 10 (x - 2) = (y - 2)^{2}

Therefore parabola properties are:

(h, k) = (2, 2), p = 10

Parabola is of the form

4 p (x - h) = (y - k)^{2}

and is symmetric around the

x

-axis

Axis of symmetry is a line parallel to the

x

-axis which intersects the vertex:

y = 2

y = \frac{1}{2} x^{2} + 2

y = 2 x^{2} - 12 x + 22

y = - 2 x^{2} + 3 x

x^{2} = 8 (y - 3)

(x - 2)^{2} = 40 (y - 2)