What is the axis y=2x^2-12x+22 ?

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axis y=2x^2-12x+22

axis

y = 2 x^{2} - 12 x + 22

x = 3

Solution steps

y = 2 x^{2} - 12 x + 22

Rewrite

y = 2 x^{2} - 12 x + 22

in the standard form

4 \cdot \frac{1}{8} (y - 4) = (x - 3)^{2}

Therefore parabola properties are:

(h, k) = (3, 4), p = \frac{1}{8}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 3

y = - 2 x^{2} + 3 x

x^{2} = 8 (y - 3)

(x - 2)^{2} = 40 (y - 2)

y = 6 x^{2} - 13 x + 6

y = 3 x^{2} + 19 x - 40