What is the axis x^2=8(y-3) ?

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axis x^2=8(y-3)

axis

x^{2} = 8 (y - 3)

x = 0

Solution steps

x^{2} = 8 (y - 3)

Rewrite

x^{2} = 8 (y - 3)

in the standard form:

4 \cdot 2 (y - 3) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 3), p = 2

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 0

(x - 2)^{2} = 40 (y - 2)

y = 6 x^{2} - 13 x + 6

y = 3 x^{2} + 19 x - 40

(x + 5)^{2} = - 2 (y - 2)

x^{2} = - 36 y