What is the axis y^2-8x=0 ?

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axis y^2-8x=0

axis

y^{2} - 8 x = 0

y = 0

Solution steps

y^{2} - 8 x = 0

Rewrite

y^{2} - 8 x = 0

in the standard form:

4 \cdot 2 (x - 0) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = 2

Parabola is of the form

4 p (x - h) = (y - k)^{2}

and is symmetric around the

x

-axis

Axis of symmetry is a line parallel to the

x

-axis which intersects the vertex:

y = 0

y = 18 x - \frac{3}{2} x^{2}

x = - \frac{1}{2} (y + 4)^{2} - 5

(y - 2)^{2} = - (x + 4)

y = 3 (x - 1) (x + 2)

x^{2} + 8 x + 12